Average Rounded Values of the BAC level for people of different weights.

A one-dimensional face is defined as a numeric habit in which the variables appear tho in the low degree, are multiplied by constants, and are feature only by addition and subtraction. A linear variantula would be written as y=mx+b. The sets of entropy I go out be determining linear or not are based upon the average round values for job alcohol concentration (BAC) for people of varied weights, according to how many an(prenominal) drinks they have consumed. In this case the BAC is strung-out of the amount of drinks one has guzzled down. (All my work for these problems are on a separate bed sheet of paper.) When examining the data for BAC for a one hundred twenty pound person, I inst totally the data to be linear. To broadside this I represent the slant (rate of diversity) to see if is it consistent amid all solutions of the formula. Slope is found by M(slope)=change in y divided by change in x. I tried a a few(prenominal) points from the table and foun d that the rate of change was the same between each set of data. This slope is .031; meat aft(prenominal)(prenominal) every(prenominal) drink there is a .031 increase in a 120 pound person BAC. A reasonable be given for this model is all 0-.435. Because you cant have a BAC of negative, you willing function out with energy drinks and a zero BAC.

The Domain will be 0-14. If you have a zero BAC level, than you have had zero drinks, and in this case the domain is up until fourteen drinks because after fourteen drinks you are jumpting into dangerous levels. After purpose the slope, I can now figure out the equation. Because it i s linear, I know that the equation will be i! n the form of y=mx+b. The slope is the m (.031) and the... If you want to get a full essay, order it on our website: BestEssayCheap.com

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